The PDF of RD Sharma Solutions for Exercise 2.2 of Class 7 Maths Chapter 2 Fractions are provided here. The questions present in this have been solved by BYJUâ€™S experts in Maths, and this will help students solve the problems without any difficulties. This exercise contains fifteen questions with many sub-questions which deals with the multiplication of integers. By practising sincerely, the students can obtain worthy results in board exams using the RD Sharma Solutions for Class 7.

## Download the PDF of RD Sharma Solutions For Class 7 Maths Chapter 2 – Fractions Exercise 2.2

### Access answers to Maths RD Sharma Solutions For Class 7 Chapter 2 – Fractions Exercise 2.2

Exercise 2.2 Page No: 2.19

**1. Multiply:**

**(i) (7/11) by (3/5)**

**(ii) (3/5) by 25**

**(iii) 3 4/15 by 24**

**(iv) 3 1/8 by 4 10/11**

**Solution:**

(i) Given (7/11) by (3/5)

We have to multiply the given number

(7/11) Ã— (3/5) = (21/55)

(ii) Given (3/5) by 25

(3/5) Ã— 25 = 15 [dividing 25 by 5]

(iii) Given 3 4/15 by 24

First convert the given mixed fraction to improper fraction.

(49/15) Ã— 24 = (1176/15)

= 78 2/5

(iv) Given 3 1/8 by 4 10/11

First convert the given mixed fractions to improper fractions.

(25/8) Ã— (54/11) = (1350/88) = (675/44)

= 15 15/44

**2. Find the product:**

**(i) (4/7) Ã— (14/25)**

**(ii) 7 1/2 Ã— 2 4/15**

**(iii) 3 6/7 Ã— 4 2/3**

**(iv) 6 11/14 Ã— 3 1/2**

**Solution:**

(i) Given (4/7) Ã— (14/25)

(4/7) Ã— (14/25) = (4 Ã— 14)/ (7 Ã— 25)

= (56/175)

Converting above fractions into simplest form

= (8/25)

(ii) Given 7 1/2 Ã— 2 4/15

We have to convert mixed fractions into improper fractions

Then we get (15/2) and (34/15)

7 (1/2) Ã— 2 (4/15) = (15/2) Ã— (34/15)

= (15 Ã— 34)/ (2 Ã— 15)

= (510/30)

= 17

(iii) Given 3 6/7 Ã— 4 2/3

We have to convert mixed fractions into improper fractions

Then we get (27/7) and (14/3)

3 6/7 Ã— 4 2/3 = (27/7) Ã— (14/3)

On simplifying

= 9 Ã— 2

= 18

(iv) Given 6 11/14 Ã— 3 1/2

We have to convert mixed fractions into improper fractions

Then we get (95/14) and (7/2)

6 11/14 Ã— 3 1/2 = (95/14) Ã— (7/2)

= (95 Ã— 7)/28

= (665/28)

= 23 3/4

**3. Simplify:**

**(i) (12/25) Ã— (15/28) Ã— (35/36)**

**(ii) (10/27) Ã— (39/56) Ã— (28/65)**

**(iii) 2 2/17 Ã— 7 2/9 Ã— 1 33/52**

**Solution:**

(i) Given (12/25) Ã— (15/28) Ã— (35/36)

= (12 Ã— 15 Ã— 35)/ (25 Ã— 28 Ã— 36)

= (6300/25200)

On simplifying we get

= (1/4)

(ii) Given (10/27) Ã— (39/56) Ã— (28/65)

= (10 Ã— 39 Ã— 28)/ (27 Ã— 56 Ã— 65)

= (10920/98280)

On simplifying we get

= (1/9)

(iii) Given 2 2/17 Ã— 7 2/9 Ã— 1 33/52

First convert the given mixed fractions into improper fractions then we get

= (36/17) Ã— (65/9) Ã— (85/52)

= (36 Ã— 65 Ã— 85)/ (17 Ã— 9 Ã— 52)

= (198900/7956)

On simplifying we get

= 25

**4. Find:**

**(i) (1/2) of 4 2/9**

**(ii) (5/8) of 9 2/3**

**(iii) (2/3) of (9/16)**

**Solution:**

(i) Given (1/2) of 4 2/9

First convert given mixed fraction into improper fraction then we get (38/9)

= (1/2) Ã— (38/9)

= (1 Ã— 38)/ (2 Ã— 9)

= (38 /18)

= 2 1/9

(ii) Given (5/8) of 9 2/3

First convert given mixed fraction into improper fraction then we get (29/3)

= (5/8) Ã— (29/3)

= (5 Ã— 29)/ (8 Ã— 3)

= (145 /24)

= 6 1/24

(iii) Given (2/3) of (9/16)

= (2/3) Ã— (9/16)

= (2 Ã— 9)/ (3 Ã— 16)

= (18 /48)

= (3/8)

**5. Which is greater? (1/2) of (6/7) or (2/3) of (3/7)**

**Solution:**

Given (1/2) of (6/7)

= (1/2) Ã— (6/7)

= (1 Ã— 6)/ (2 Ã— 7)

= (6 /14)

Also given that (2/3) of (3/7)

= (2/3) Ã— (3/7)

= (2 Ã— 3)/ (3 Ã— 7)

= (6 /21)

While comparing two fractions, if numerators of both the fractions are same, then the denominator having higher value shows the fraction has lower value.

Therefore (6/14) is greater.

Hence (1/2) of (6/7) is greater.

**6. Find:**

**(i) (7/11) of Rs 330**

**(ii) (5/9) of 108 meters**

**(iii) (3/7) of 42 liters**

**(iv) (1/12) of an hour**

**(v) (5/6) of an year**

**(vi) (3/20) of a kg**

**(vii) (7/20) of a liter**

**(viii) (5/6) of a day**

**(ix) (2/7) of a week**

**Solution:**

(i) Given (7/11) of Rs 330

= (7/11) Ã— 330

On dividing by 11 we get

= 7 Ã— 30

= 210

(7/11) of Rs 330 is Rs 210

(ii) Given (5/9) of 108 meters

= (5/9) Ã— 108

Dividing 108 by 9 we get

= 5 Ã— 12

= 60

(5/9) of 108 meters is 60 meters

(iii) Given (3/7) of 42 liters

= (3/7) Ã— 42

Dividing 42 by 7 we get

= 3 Ã— 6

= 18

(3/7) of 42 liters is 18 liters

(iv) Given (1/12) of an hour

An hour = 60 minutes

= (1/12) Ã— 60

Dividing 60 by 12 we get

= 1 Ã— 5

= 5

(1/12) of an hour is 5 minutes

(v) Given (5/6) of an year

1 year = 12 months

= (5/6) Ã— 12

Dividing 12 by 6 we get

= 5 Ã— 2

= 10

(5/6) of an year is 10 months

(vi) Given (3/20) of a kg

1 kg = 1000 grams

= (3/20) Ã— 1000

= 3 Ã— 50

= 150

(3/20) of a kg is 150 grams

(vii) Given (7/20) of a liter

1 liter = 1000 ml

= (7/20) Ã— 1000

= 7 Ã— 50

= 350

(7/20) of a liter is 350ml

(viii) Given (5/6) of a day

1 day = 24 hours

= (5/6) Ã— 24

= 5 Ã— 4

= 20

(5/6) of a day is 20 hours

(ix) Given (2/7) of a week

1 week = 7 days

= (2/7) Ã— 7

= 2 Ã— 1

= 2

(2/7) of a week is 2 days

**7. Shikha plants 5 saplings in a row in her garden. The distance between two adjacent saplings is Â¾ m. Find the distance between the first and the last sapling.**

**Solution:**

Given that the distance between two adjacent saplings is (3/4) m

There are 4 adjacent spacing for 5 sapling

Therefore, distance between the first and the last sapling is

= (3/4) Ã— 4

= 3

The distance between them is 3m

**8. Ravish reads (1/3) part of a book in 1 hour. How much part of the book will he read in 2 1/5 hours?**

**Solution:**

Given Ravish takes 1 hour to read (1/3) part of the book

Then we have to calculate how much part he will read in 2 1/5 hours

First convert the given mixed fraction into improper fraction i.e. (11/5)

Now let x be the full part of book

1 hour = (1/3) x

Remaining part of the book, he will read in

= (11/5) Ã— (1/3) x

= (11/15) part of the book

**9. Lipika reads a book for 1 3/4 hours every day. She reads the entire book in 6 days. How many hours in all were required by her to read the book?**

**Solution:**

Given time taken by Lipika to read a book per day = 1 3/4 = (7/4) hours

Time taken by Lipika to read a book in 6 days = (7/4) Ã— 6

= (42/4)

= 10 Â½ hours

**10. Find the area of a rectangular park which is 41 2/3 m along and 18 3/5 m broad.**

**Solution:**

Given length of rectangular park is = 41 2/3 = (125/3)

Breadth of rectangular park is = 18 3/5 = (93/5)

Area of rectangular park = length Ã— breadth

= (125/3) Ã— (93/5)

= (125 Ã— 93)/15

= (11625/15)

= 775 m^{2}

**11. If milk is available at Rs 17 3/4 per liter, find the cost of 7 2/5 liters of milk.**

**Solution:**

Given the cost of milk per liter is = 17 3/4 = Rs (71/4)

And the cost of 7 2/5 = (37/5) is

= (37/ 5) Ã— (71/4)

= (37 Ã— 71)/20

= (2627/20)

= Rs 131 7/20

**12. Sharada can walk 8 1/3 km in one hour. How much distance will she cover in 2 2/5 hours?**

** **

**Solution: **

Given distance covered by Sharada in one hour = 8 1/3 = (25/3) km

Distance covered by her in 2 2/5 hours = (12/5) is

= (25/3) Ã— (12/5)

= (25 Ã— 12)/15

= (300/15)

= 20 km

**13. A sugar bag contains 30kg of sugar. After consuming (2/3) of it, how much sugar is left in the bag?**

**Solution:**

A sugar bag contains 30kg of sugar.

After consuming, the left sugar in the bag is = 30- (2/3) Ã— 30

= 30 – 2 Ã— 10

= 30 â€“ 20

= 10kg

**14. Each side of a square is 6 2/3 m long. Find its area.**

**Solution:**

Side of a square = 6 2/3 = (20/3) m

Area of square = side Ã— side

= (20/3) Ã— (20/3)

= (400/9)

=44 4/9 m^{2}

**15. There are 45 students in a class and (3/5) of them are boys. How many girls are there in the class?**

**Solution:**

Total number of students = 45

Number of boys out of 45 is = (3/5)

Number of girls = 45 â€“ (3/5) Ã— 45

= 45 â€“ 3 Ã— 9

= 45 â€“ 27

= 18 girls

## RD Sharma Solutions for Class 7 Maths Chapter – 2 Fractions Exercise 2.2

Exercise 2.2 of RD Sharma Solutions for Class 7 Maths Chapter 2 Fractions explains the fundamental operations on fractions. In this exercise, we shall study on how to multiply mixed fractions with improper fractions, proper fractions and mixed fractions.